4/3x^2-48=0

Solution for 4/3x^2-48=0 equation:

4/3x^2-48=0


Domain of the equation: 3x^2!=0

x^2!=0/3

x^2!=√0

x!=0

x∈R


We multiply all the terms by the denominator


-48*3x^2+4=0

Wy multiply elements

-144x^2+4=0

a = -144; b = 0; c = +4;
Δ = b2-4ac
Δ = 02-4·(-144)·4
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-48}{2*-144}=\frac{-48}{-288}
=1/6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+48}{2*-144}=\frac{48}{-288}
=-1/6
$